Change the encode function so that punctuation is simply skipped.

Question

What will be an ideal response?

Answer 1

```
def encode(string,keyletters):
alpha="abcdefghijklmnopqrstuvwxyz" secret = ""
for letter in string:
if not letter.lower() in ",.?:;-_'!":
index = alpha.find(letter)
secret = secret+keyletters[index]
print secret
```

Note: This code does not skip spaces, but one could add a space to the check against string to accomplish that.