Solve the problem.A projectile is fired from a height of 9.8 feet with an initial velocity of 188 ft/sec at an angle of 48° with the horizontal. The parametric equations for the path of the projectile are x = (188 cos 48°)t, and y = 9.8 + (188 sin 48°)t - 16t2,where x and y are in feet and t is in seconds. Determine the maximum height reached by the projectile. Round your answer to the nearest tenth of a foot.

A. 324.6 ft
B. 619.8 ft
C. 314.8 ft
D. 305 ft


Answer: C

Mathematics

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