How many distinguishable permutations of letters are possible in the word?BASEBALL
A. 5040
B. 10,080
C. 20,160
D. 40,320
Answer: A
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Solve the problem.A company adopts an advertising campaign to weekly add to its customer base. It assumes that as an average fifty percent of its new customers, those added the previous week, will bring in one friend, but those who have been customers longer will not be very effective as recruiters and can be discounted. A media campaign brings in 10,000 customers initially. What is the expected total number of customer with whom the company can expect to have dealings?
A. 15,000 B. 30,000 C. 20,000 D. The sum diverges to infinity.
Write the negation of the compound statement.
?
?
A. ?
B. ?
C. ?
D. ?
E. ?
A property owner has several rental units and wants to build more. How much of each month's rental income should be deposited at the beginning of each month in an account that earns an annual rate of 6.8%, compounded monthly, if the goal is to have $150,000 at the end of 7 years? Round your answer to the nearest cent.
A. $3,155.45 B. $1,391.38 C. $1,742.00 D. $2,270.66 E. $1,142.50
A candidate must decide whether he should spend his time and money on TV commercials or making personal appearances. His staff determines that by using TV he can reach 110,000 people with probability 0.06, 55,000 people with probability 0.39, and 30,000 people with probability 0.55; by making personal appearances he can reach 80,000 people with probability 0.04, 60,000 people with probability 0.36, and 25,000 people with probability 0.6. In the following table, x represents the number of people reached by each choice. In each case, find the expected value of x to decide which method, if either, will reach more people. ? TV CommercialsPersonal AppearancesxPr(x)xPr(x)110,0000.0680,0000.0455,0000.3960,0000.3630,0000.5525,0000.6?
A. ?
?
B. ?
?
C. ?
?
D. ?
?
E. ?
