Solve the problem.One side of a triangle is twice as long as a second side. The third side of the triangle is 14 feet long. The perimeter of the triangle cannot be more than 53 feet. Find the longest possible values for the other two sides of the triangle.
A. 20 feet and 20 feet
B. 34 feet and 34 feet
C. 13 feet and 26 feet
D. 12 feet and 24 feet
Answer: C
You might also like to view...
Find a formula for the nth term of the sequence.0, 
, 0, 
, 0 (alternating 0's and 
's)
A. an = 
B. an = 
C. an = 
D. an = 
Perform the indicated operations and simplify the result. Leave the answer in factored form.
- 
A. 
B. - 
C. 
D. - 
Solve for x.
?
?
, b = 1
?
A. x = 1 B. x = 7 C. x = 3 D. x = 5 E. x = 4
Solve the problem.The height of a ball thrown is given by 
, where x is the horizontal distance in feet traveled. At what distances will the height of the ball be more than 
(Round distances to the nearest tenth of a foot, if necessary.)
A. 0 ft < x < 5.9 ft or 19.1 ft < x < 25 ft B. 5.9 ft < x < 25 ft C. 0 ft < x < 19.1 ft D. 5.9 ft < x < 19.1 ft