Solve the problem.Suppose that the acceleration of an object is given by a(t) = 5t2/3 + 2e-t. The velocity of the object at time 0 is v(0) = 12 and its position at time 0 is s(0) = -7. Find s(t).
A. 3t5/3 - 2e-t + 14
B. 
+ 2e-t + 10t - 9
C. 
+ 2e-t + 12t - 7
D. 
+ 2e-t +14t - 9
Answer: D
Mathematics
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