Find the equation of the circle that satisfies the following conditions. Express the final equation in the form x2 + y2 + Dx + Ey + F = 0.Tangent to the x axis, a radius of length 3, and abscissa of center is -7
A. x2 + y2 - 14x - 6y + 49 = 0 and x2 + y2 - 14x + 6y + 49 = 0
B. x2 + y2 + 14x - 6y + 49 = 0
C. x2 + y2 + 14x - 6y + 49 = 0 and x2 + y2 + 14x + 6y + 49 = 0
D. x2 + y2 + 14x + 6y + 49 = 0
E. x2 + y2 - 14x + 6y + 49 = 0
Answer: C
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