Graph the quadratic function. Determine the vertex, find the equation of the axis of symmetry, find any x- and y-intercepts, and state the domain and range in interval notation.f(x) = x2 - 2x + 1
A. vertex: (-1, 1)
axis of symmetry: x = -1
x-intercept: none; y-intercept: 2
domain: (-?, ?); range: [1, ?)
B. vertex: (1, 0)
axis of symmetry: x = 1
x-intercept: 1; y-intercept: 1
domain: (-?, ?); range: [0, ?)
C. vertex: (1, 1)
axis of symmetry: x = 1
x-intercept: none; y-intercept: 2
domain: (-?, ?); range: [1, ?)
D. vertex: (-1, 0)
axis of symmetry: x = -1
x-intercept: -1; y-intercept: 1
domain: (-?, ?); range: [0, ?)
Answer: B
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Solve the problem.Use the following information to graph the function f over the closed interval [-5, 6].i) The graph of f is made of closed line segments joined end to end.ii) The graph starts at the point (-5, 1).iii) The derivative of f is the step function in the figure shown here.
A. 
B. 
C. 
D. 
Match the equation with the surface it defines.
+ 
= 
A. Figure 3 B. Figure 4 C. Figure 2 D. Figure 1
Rationalize the denominator. If any variables are present, assume that they represent nonnegative numbers, and assume that the denominator is not zero.
A. 
B. 
C. 
D. 1
Graph the function.y = 
A. 
B. 
C. 
D. 