Use the given table for y = ax2 + bx + c to solve ax2 + bx + c < 0 or ax2 + bx + c > 0, as indicated.y = x2 + 16x; ax2 + bx + c > 0

A. -4 < x < 0
B. -16 < x < 0
C. x < -4 or x > 0
D. x < -16 or x > 0


Answer: D

Mathematics

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Mathematics