Use the Principle of Mathematical Induction to show that the statement is true for all natural numbers n.
n = 67n
What will be an ideal response?
First we show that the statement is true when n = 1.
For n = 1, we get 67 = 6(7?1) = 67
This is a true statement and Condition I is satisfied.
Next, we assume the statement holds for some k. That is,
is true for some positive integer k.
We need to show that the statement holds for k + 1. That is, we need to show that
So we assume that is true and multiply the next term,
to both sides of the equation.
k
(k + 1) = 67k
(k + 1)
(k + (k + 1)) = 67k
(2k + 1) = 6(7k + 7k + 7))
6(7(2k + 1)) = 6(7(2k + 1))
Condition II is satisfied. As a result, the statement is true for all natural numbers n.
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