Use the Principle of Mathematical Induction to show that the statement is true for all natural numbers n.n = 67n

What will be an ideal response?


First we show that the statement is true when n = 1.
 For n = 1, we get 67 = 6(7?1) = 67
This is a true statement and Condition I is satisfied.

Next, we assume the statement holds for some k. That is,
  is true for some positive integer k.
We need to show that the statement holds for k + 1. That is, we need to show that
 
So we assume that  is true and multiply the next term,  to both sides of the equation.
 k(k + 1) = 67k(k + 1)
 (k + (k + 1)) = 67k
 (2k + 1) = 6(7k + 7k + 7))
 6(7(2k + 1)) = 6(7(2k + 1))
Condition II is satisfied. As a result, the statement is true for all natural numbers n.

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