Find the value(s) of the variable for which the rational expression is undefined.
A. 8, 4
B. 0, 8, -4
C. 8, -4
D. 0, 8, 4
Answer: B
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Match the equation with the surface it defines.x2 + y2 = 16 
A. Figure 2 B. Figure 1 C. Figure 4 D. Figure 3
Provide an appropriate response.The test scores of 32 students are listed below. 32 37 41 44 46 48 53 55 57 57 59 63 65 66 68 69 70 71 74 74 75 77 78 79 81 82 83 86 89 92 95 99Construct a boxplot for the data set.
A. 
B. 
C. 
D. 
Solve.Margaret earns $13.04 per hour at her job. She worked 15 hours last week. Calculate Margaret's pay before taxes.
A. $193.77 B. $193.50 C. $195.60 D. $195.46
Solve the problem.The table below lists women's and men's total enrollments at all institutions of higher learning in Country X for various years. College Enrollments (Millions)YearWomenMen19886.35.919907.46.519948.16.820028.97.120069.27.4The enrollments (in millions) of women and men, respectively, can be modeled by the systemW = 0.14t + 5.69M = 0.07t + 5.62where t is the number of years since 1980.(i) Use "intersect" on a graphing calculator to estimate when women's and men's enrollments were approximately equal. What was that enrollment?(ii) Use the models to predict the total enrollment of women and men in 2011.
A. (i) Intersect at approximately (-2.20, 5.98). This means that in 1978, women's and men's enrollment was about 6.0 million students. (ii) Not enough information has been provided. B. (i) Intersect at approximately (-1.00, 5.55). This means that in 1979, women's and men's enrollment was about 5.6 million students. (ii) In 2011, W = 10.03 million students and M = 7.79 million students. C. (i) Intersect at approximately (-1.11, 6.32). This means that in 1979, women's and men's enrollment was about 6.3 million students. (ii) In 2011, so W = 10.31 million students and M = 7.93 million students. D. (i) The functions do not intersect. (ii) In 2011, W = 9.47 million students and M = 7.51 million students.