Given the polynomial function f(x), find the rational zeros, then the other zeros (that is, solve the equation 
), and factor f(x) into linear factors.f(x) = x3 - 3x2 + 7x - 5
A. -1, 1 + 2i, 1 - 2i; f(x) = (x + 1)(x - 1 - 2i)(x - 1 + 2i)
B. 1, 1 + 2i, 1 - 2i; f(x) = (x - 1)(x - 1 - 2i)(x - 1 + 2i)
C. 1, 1 + 
, 1 - 
; f(x) = (x - 1)(x - 1 - 
)(x - 1 +
)
D. 1, -1 + 2i, -1 - 2i; f(x) = (x - 1)(x + 1 - 2i)(x + 1 + 2i)
Answer: B
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A ladder leans against a wall so that its slope is 3.61 feet per foot. The top of the ladder is 11 vertical feet above the ground. What is the horizontal distance from the base of the ladder to the wall? (Assume that the positive direction points from the base of the ladder toward the wall.) ?
A. 3.05 feet B. 0.33 feet C. 3.15 feet D. 0.95 feet
Solve the problem.Consider the area of the region in the first quadrant enclosed by the curve y = 
cosh 7x, the coordinate axes, and the line x = 8. This area is the same as the area of a rectangle of a length s, where s is the length of the curve from 
to 
What is the height of the rectangle?
A. 
B. 
sinh 56
C. 7
D. sinh 56
The planet Mercury travels in an elliptical orbit with eccentricity 0.703. Its minimum distance from the Sun is  FIGURE 1.png)
km. If the perihelion distance from a planet to the Sun is a(1 - e) and the aphelion distance is a(1 + e), find the maximum distance (in km) from Mercury to the Sun.
 multiple choice.png)
Solve. If necessary, round to the nearest tenth.If a flagpole 21 feet tall casts a shadow that is 28 feet long, find the length of the shadow cast by an antenna which is 33 feet tall.
A. 44 ft B. 24.8 ft C. 40 ft D. 17.8 ft