Calculate the amount of 5% sodium chloride solution needed to prepare 400 mL of 0.9% sodium chloride solution, using water as the diluent: ________.
Fill in the blank(s) with the appropriate word(s).
72 mL
Use the alligation method. A total of 0.9 part of 5% sodium chloride solution and 4.1 parts of water are needed, for a total of 5 parts.
400 mL needed ÷ 5 parts = 80 mL per part
80 mL × 0.9 = 72 mL of sodium chloride
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