A box contains 15 resistors. Ten of them are labeled 50 ? and the other five are labeled 100 ?.
a. What is the probability that the first resistor is 100 ??
b. What is the probability that the second resistor is 100 ?, given that the first resistor is 50 ??
c. What is the probability that the second resistor is 100 ?, given that the first resistor is 100 ??
(a) 5?15
(b) Given that the first resistor is 50?, there are 14 resistors remaining of which 5 are 100?. Therefore P(2nd is 100?|1st is 50?) = 5?14.
(c) Given that the first resistor is 100?, there are 14 resistors remaining of which 4 are 100?. Therefore P(2nd is 100?|1st is 100?) = 4?14
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