Decide what values of the variable cannot possibly be solutions for the equation.
+
= 11
A. 1
B. -1, 0, 1
C. -1, 0
D. -1, 1
Answer: A
Mathematics
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A. 287 mg B. 283 mg C. 144 mg D. 496 mg
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Solve for the indicated variable.v = p - k ln t, for t
A. t = e(v - p)/k
B. t = e(p - v)/k
C. t =
D. t = ln
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Represent the shaded area in the figure group with an improper fraction.
A.
B.
C.
D.
Mathematics