Write the English phrase as an algebraic expression. Let the variable x represent the number.six less than the product of 11 and a number
A. 6 - 11x
B. 6x - 11
C. 11x + 6
D. 11x - 6
Answer: D
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Solve the problem.The hyperbola 
- 
= 1 is shifted down 6 units and right 7 units. Find an equation for the new hyperbola and find the new center.
A. 
- 
= 1; center: (7, -6)
B. 
+ 
= 1; center: (-6, 7)
C. 
- 
= 1; center: (7, -6)
D. 
- 
= 1; center: (6, -7)
Integrate the function.
A. 
tan3 x + C
B. - 
tan3 x + C
C. 8(sec x + tan x)5+ C
D. 8 tan x + 
tan3 x + C
Find the coordinates of the vertex and the intercepts of the quadratic function. When necessary, approximate the x-intercepts to the nearest tenth.f(x) = x2 - 10x - 11
A. V(5, -6); I(0, 11); (-11, 0); (11, 0) B. V(5, 6); I(0, 11; (1, 0); (-11, 0) C. V(-5, -36); I(0, -11); no x-intercepts D. V(5, -36); I(0, -11); (11, 0); (-1, 0)
Graph the function. State the amplitude, period, and phase shift.y = 4
sin x + 4 cos x
x-scale = 
y-scale = 10
A. Amplitude 4, period 2?, phase shift - 
x-scale =  | y-scale = 10 |
B. Amplitude 8, period ?, phase shift -
x-scale =  | y-scale = 10 |
C. Amplitude 8, period 2?, phase shift -
x-scale =  | y-scale = 10 |
D. Amplitude 4, period ?, phase shift -
x-scale =  | y-scale = 10 |