Determine the probability (assuming normal distribution) that a car would need engine maintenance between 70,000 and 90,000 miles.
What will be an ideal response?
The value 70000 is below the mean value and the z value corresponding to 70000 is determined from
A = 0.4706. Similarly, the value 90000 is below the mean value and the z score corresponding to 90000 is computed from
A = 0.3238. Therefore, the probability that a car would need engine maintenance between 70000 and 90000 miles is 0.4706-0.3238 = 0.1468
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