Provide an appropriate response.Why does a function defined by a polynomial of degree five with real coefficients have either 1, 3, or 5 real zeros counting multiplicities?
What will be an ideal response?
By the Fundamental Theorem of Algebra and the Factor Theorem, the polynomial has five complex, not necessarily real, zeros. By the Conjugate Zeros Theorem, the nonreal zeros among these come in pairs, so there are 0, 2, or 4 nonreal zeros. That leaves 5, 3, or 1 real zeros.
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Decide whether or not the ordered pair satisfies the system of linear equations.(4, -5);
A. Yes B. No
Sketch the graph of the given equation over the interval [-2?, 2?].y = -2 cos x
A.
B.
C.
D.
Use the right triangle shown and find the missing length. If necessary, round to three decimal places. c = 14, b = 3
A. 13.675 B. 3.317 C. 4.123 D. 14.318
Factor completely. If the polynomial is prime, state this.a2 + 25ab + 24b2
A. (a + 24b)(a + b) B. (a + b)(24a + b) C. (ab + 24)(ab + 1) D. (a + 25b)(a + b)