Solve the problem.Show that the midpoint of the hypotenuse of a right triangle is equidistant from all three vertices. [Hint: See the figure below. Show that
=
.] 
What will be an ideal response?
Verify that =
.
Cancel the 2's and square both sides:2 =
2 or
(a + b)?(a + b) = (a - b)?(a - b) or
a?a + 2a?b + b?b = a?a - 2a?b + b?b [2a?b = 0 since a and b are orthogonal]
a?a + b?b = a?a + b?b Verified.
Thus, the midpoint is equidistant from all three vertices.
You might also like to view...
Perform the indicated operation without the use of a calculator and express each answer in decimal notation.
A. 0.00142857 B. 700 C. 100 D. 0.07
Evaluate the cylindrical coordinate integral.
A. 50? B. 100 C. 150 D. 150?
Find the domain of the function.y = 10 +
A. (-?, -3) B. (-3, ?) C. all real numbers except 3 D. all real numbers except -3
Write the system in the form Then solve the linear system by computing
with a calculator. Round numbers to the nearest tenth, as necessary.2.8x + 16.6y + 4.8z = 1.94.7x - 7.0y - 0.6z = -3.74.5x + 9.4y - 0.9z = 10.5
A. (0.3, 1.8, -5.5) B. (0.1, 0.4, -1.1) C. (0.1, 0.8, -2.5) D. (0.0, 0.2, -0.5)