Solve the problem.The length of a rectangle is 4 inches more than its width. If 2 inches are taken from the length and added to the width, the figure becomes a square with an area of 144 square inches. What are the dimensions of the original figure?

A. 8 in. by 12 in.
B. 12 in. by 12 in.
C. 10 in. by 12 in.
D. 10 in. by 14 in.


Answer: D

Mathematics

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Find the distance between points P1 and P2. P1(6, 3, -7) and P2(11, 7, -4)

A. 50
B. 5;
C. 10
D. 25

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Subtract the polynomials.(-5x6 + 5x8 + 4 + 6x7) - (5 + 8x7 + 7x8 + 3x6)

A. -2x8 - 2x7 - 8x6 - 1 B. 12x8 + 14x7 - 2x6 - 1 C. 12x8 + 14x7 - 2x6 + 9 D. -2x8 + 14x7 - 2x6 + 9

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Graph the equation.25y = 5x + 25

A.

B.

C.

D.

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Provide an appropriate response.Use -1 =  to solve .

What will be an ideal response?

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