Air is heated from 20°C to 100°C. Determine the change in specific internal energy and the change in specific enthalpy for the air, assuming ideal gas with constant specific heat behavior.
Given: T1 = 20°C; T2 = 100°C
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Properties for air: cp = 1.005 kJ/kg-K, cv = 0.718 kJ/kg-K at 300 K.
For an ideal gas with constant specific heats:
?u = cv (T2 – T1) = (0.718 kJ/kg-K) (100°C – 20°C) = 57.4 kJ/kg
?h = cp (T2 – T1) = (1.005 kJ/kg-K) (100°C – 20°C) = 80.4 kJ/kg
Recall that the change in °C is the same numerically as the change in K, for the temperature.
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