Find the partial fraction decomposition for the rational expression.
A. 
+ 
B. 
+ 
C. 
+ 
D. 
+ 
Answer: D
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Provide an appropriate response.When solving a rational equation with a variable denominator, a value obtained that makes a denominator 0 is called a(n) 
.
A. no solution B. complex fraction C. extraneous solution D. rational equation
Shown here are graphs of y1 and y2. The point whose coordinates are given at the bottom of the screen lies on the graph of y1. Use this graph, and not your own calculator, to find the value of y2 for the same value of x shown.
A. -32 B. -2 C. -8 D. 2
Find the equation that the given graph represents and give the domain, range, and interval(s) over which the function is increasing and decreasing.
A. P(x) = -x5 - 3x2 + 6; domain: (-?, ?); range: [3.75, ?); Increasing over [-2.21, 0] and [2.21, ?); Decreasing over (-?, -2.21] and [0, 2.21] B. P(x) = x4 - 3x2 + 6; domain: (-?, ?); range: [3.75, ?); Increasing over [-1.24, 0] and [1.24, ?); Decreasing over (-?, -1.24] and [0, 1.24] C. P(x) = x5 + 2x3 + 6; domain: (-?, ?); range: [4.86, ?); Increasing over [-1.64, 0] and [1.64, ?); Decreasing over (-?, -1.64] and [0, 1.64] D. P(x) = x6 - 2x2 - 6; domain: (-?, ?); range: [4.86, ?); Increasing over [-.98, 0] and [.98, ?); Decreasing over (-?, -.98] and [0, .98]
Rotate the axes so that the new equation contains no xy-term. Discuss the new equation.31x2 + 10
xy + 21y2 -144 = 0
A. ? = 45°
x'2 = -4
y'
parabola
vertex at (0, 0)
focus at (0, -
)
B. ? = 45°
y'2 = -4
x'
parabola
vertex at (0, 0)
focus at (-
, 0)
C. ? = 30°
+ 
= 1
ellipse
center at (0, 0)
major axis is y'-axis
vertices at (0, ±3)
D. ? = 36.9°
+ 
= 1
ellipse
center at (0, 0)
major axis is x'-axis
vertices at (±3, 0)