Find the x- and y-intercepts for the equation. Then graph the equation.y = 
x - 6
A. x-intercept: (12, 0), y-intercept: (0, -6)
B. x-intercept: (6, 0), y-intercept: (0, -6)
C. x-intercept: (-12, 0), y-intercept: (0, -6)
D. x-intercept: (-12, 0), y-intercept: (0, 6)
Answer: A
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Perform the operation indicated.1.91 ÷ 5
A. 0.482 B. 0.0482 C. 0.382 D. 0.0382
Solve the problem.The wind chill factor represents the equivalent air temperature at a standard wind speed that would produce the same heat loss as the given temperature and wind speed. One formula for computing the equivalent temperature is W(t) = 
where v represents the wind speed (in meters per second) and t represents the air temperature 
. Compute the wind chill for an air temperature of 15°C and a wind speed of 12 meters per second. (Round the answer to one decimal place.)
Fill in the blank(s) with the appropriate word(s).
Tell whether a linear model or a quadratic model is appropriate for the data. If a quadratic model is appropriate, then decide also whether the lead coefficient should be positive or negative.
A. Quadratic; leading coefficient positive B. Linear C. Quadratic; leading coefficient negative
Match the given graph with its polynomial function.
A. f(x) = -x4 + x2 - 3x - 4 B. f(x) = 2x4 - x2 + 4 C. f(x) = -x3 - x - 4 D. f(x) = 2x3 + x2 - 3x + 4