Translate the situation into mathematical language. You need not actually solve the problem.Find two consecutive integers such that 3 times the first plus 7 times the second is 107.
A. Let h be the first integer; 7h(3(h + 1)) = 107
B. Let h be the first integer; 3h + 7(h + 1) = 107
C. Let h be the first integer; 7h + 3(h + 1) = 107
D. Let h be the first integer; 3h - 7(h + 1) = 107
Answer: B
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