Using Thevenin's Theorem, find the equivalent circuit for a low pass filter when R1 = 5.6 Kê, R2 = 6.8 Kê, R3 = 10 Kê, and C = 1200 pF.
a. RTH = 13.1 Kê, C = 1200 pF, output across R
b. RTH = 2.3 Kê, C = 1200 pF, output across C
c. RTH = 11.2 Kê, C = 1200 pF, output across C
d. RTH = 12.4 Kê, C = 848 pF, output across R
e. RTH = 13.2 Kê, C = 1200 pF, output across R
b. RTH = 2.3 Kê, C = 1200 pF, output across C
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