In the problem, t is a real number and P = (x, y) is the point on the unit circle that corresponds to t. Find the exact value of the indicated trigonometric function of t.(- 
, 
)Find cos t.
A. - 
B. - 
C. 
D. - 
Answer: D
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The question(s) that follow refer to the problem of finding the minimum spanning tree for the weighted network shown below.
Using Kruskal's algorithm, which edge should we choose third?
A. DE B. EF C. BE D. DF E. none of these
Multiply.(x + 9)(x - 9)
A. x2 + 18x - 81 B. x2 - 81 C. x2 - 18 D. x2 - 18x - 81
An objective function and a system of linear inequalities representing constraints are given. Graph the system of inequalities representing the constraints. Find the value of the objective function at each corner of the graphed region. Use these values to determine the maximum value of the objective function and the values of x and y for which the maximum occurs.Objective Functionz = 7x - 6yConstraintsx ? 0 0 ? y ? 5 x - y ? 9 x + 2y ? 12
A. Maximum: 63; at (9, 0) B. Maximum: -30; at (0, 5) C. Maximum: -16; at (2, 5) D. Maximum: 64; at (10, 1)
Solve the problem.A company has three different marketing strategies that produce different results depending upon whether inflation is above 6%, between 3% and 6% inclusive, or below 3% annually. The experts cannot predict inflation for the next year. The company has three plans of action and will implement these at varying percentages of its total operation. The payoff matrix for these three plans is given below, with values given in hundred thousands. What is the market strategy for the company that will yield the best expected value? 
A. The company should use Plan 1 with probability 1, Plan 2 with probability 0, and Plan 3 with probability 0. B. The company should use Plan 1 with probability 0, Plan 2 with probability 1, and Plan 3 with probability 0. C. The company should use Plan 1 with probability 5/13, Plan 2 with probability 0, and Plan 3 with probability 8/13. D. The company should use Plan 1 with probability 1/3, Plan 2 with probability 1/3, and Plan 3 with probability 1/3.