Determine the specific energy of air at 25oC, traveling at 35.0 m/s at a height of 10.0 m. Consider the specific internal energy of the air to be 212.6 kJ/kg.
Given: T= 25oC ; z = 10.0 m; V = 35.0 m/s; u = 212.6 kJ/kg
Assume: g = 9.81 m/s2
e = u + ½ V2 = gz = 212.6 kJ/kg + ½ (35.0 m/s)2/(1000 J/kJ) + (10.0 m)(9.81 m/s2) /(1000 J/kJ) e = 213.3 kJ/kg
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