Find the center, transverse axis, vertices, foci, and the equations of the asymptotes of the hyperbola.x2 - 16y2 - 8x + 32y - 16 = 0

A. center at (4, 1)
transverse axis: x = 4
vertices: (4, -3) and (4, 5)
foci: (4, 1 - ) and (4, 1 + )
asymptotes: y + 1 = - 4(x + 4) and y + 1 = 4(x + 4)
B. center: (4, 1)
transverse axis: y = 1
vertices: (3, 1) and (5, 1)
foci: (4 - , 1) and (4 + , 1)
asymptotes: y - 1 = - 4(x - 4) and y - 1 = 4(x - 4)
C. center: (4, 1)
transverse axis: y = 1
vertices: (0, 1) and (8, 1)
foci: (4 - , 1) and (4 + , 1)
asymptotes: y - 1 = - (x - 4) and y - 1 = (x - 4)
D. center: (1, 4)
transverse axis: y = 4
vertices: (-3, 4) and (5, 4)
foci: (1 - , 4) and (1 + , 4)
asymptotes: y - 4 = - (x - 1) and y - 4 = (x - 1)


Answer: C

Mathematics

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