Solve the problem.A projectile is fired with an initial velocity of 500 feet per second at an angle of 45° with the horizontal. To the nearest foot, find the maximum altitude of the projectile. The parametric equations for the path of the projectile are x = (500 cos 45°)t, and y = (500 sin 45°)t - 16t2.
A. 1,945 feet
B. 1,953 feet
C. 1,969 feet
D. 1,936 feet
Answer: B
Mathematics
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