Determine the amount of concrete, reinforcing, forms, and accessories required the Real Estate Office in Appendix E. Using the labor rates from Problem 7-31 and the crew rate for the concrete crew from Problem 7-32 determine the cost of the concrete.
What will be an ideal response?
The following quantities can be extracted from the model.
The foundations are found under walls. Wood framed walls must be filtered out and the walls sorted by width. The 8-inch walls represent the foundation wall and the 2-foot walls represent the footings. The footings must be taken off as follows:
Length of perimeter footing = 73?4?? + 47?4?? + 73?4?? + 47?4?? = 241?4??
Volume of perimeter footing = 241?4?? × 1? × 2? = 483 ft3 = 17.88 yd3
Length of interior footings = 70?8?? + 70?8?? = 141?4??
Volume of interior footings = 141?4?? × 8?? × 2? = 188 ft3 = 6.98 yd3
Concrete volume = 17.88 yd3 + 6.98 yd3 = 24.86 yd3
You need 483 feet (241?4?? × 2) of 12-inch-high forms and 283 feet (141?4?? × 2) of 8-inch-high forms.
Horizontal #4 rebar = 3 × (241?4?? + 141?4??) = 1,148? × 1.1 = 1,263?
Dowels length (assume 2?? cover) = 10?? + 10?? + 18?? = 38??
Number of #4 dowels = 241?4?? / 16?? = 181 + 1 = 182
#4 rebar for dowels = 182 × 38?? = 576?
Anchor bolts = 141?4?? / 16?? =106 + 1 = 107
The foundation is taken off as follows:
Length of foundation = 72? + 48?8?? + 72? + 48?8?? = 241?4??
Concrete volume = 241?4?? × 8?? × 1?8?? = 268 ft3 = 9.93 cy3
Forms = 241?4?? × 1?8?? × 2 sides = 805 sfca
Horizontal #4 rebar = 241?4?? × 3 = 724 ? × 1.1 = 796?
Slab dowels = 241?4?? / 16?? = 181 + 1 = 182
#4 rebar for slab dowels = 182 × 32?? = 486?
Anchor bolts = 241?4?? / 16?? = 181 + 1 = 182
#4 rebar = 1,263? + 576? + 796? + 486? = 3,121? × 0.668 pounds per lf = 2,085 pounds
Concrete slab = 72? × 50? × 4?? = 1,200 ft3 = 44.44 yd3
Sample pricing is found in Real Estate Office.xlsm on the instructor’s website and will vary based on the assumptions made by the estimator.
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