A consumer advocate group selects a random sample of 205 snack foods and finds that 174 of them contain more fat grams than what is indicated in the snack's nutritional information. Create a 90% confidence interval for the population proportion for snack foods that contain more fat grams that what is indicated in the snack's nutritional information. Enter the lower and upper bounds for the interval in the following boxes, respectively.
Ans:
Sample proportion=174/205=0.849
n=205
90% confidence interval for the population proportion
=0.849+/-1.645*sqrt(0.849*(1-0.849)/205)
=0.849+/-0.041
=(0.808, 0.890)
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