A deuteron is accelerated from rest through a 10-kV potential difference and then moves perpendicularly to a uniform magnetic field with B = 1.6 T. What is the radius of the resulting circular path? (deuteron: m = 3.3 × 10?27 kg, q = 1.6 × 10?19 C)
A. 19 mm
B. 13 mm
C. 20 mm
D. 10 mm
E. 9.0 mm
Answer: B
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