Solve the problem.A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 296 feet of fencing and does not fence the side along the street, what is the largest area that can be enclosed?
A. 16,428 ft2
B. 10,952 ft2
C. 21,904 ft2
D. 5476 ft2
Answer: B
You might also like to view...
Find the unit tangent vector T and the principal unit normal vector N. r(t) = (ln(cos t) + 1)i + 3j + (7 + t )k, -?/2 < t < ?/2
A. T = (sin t)i + (cos t)k; N = (cos t)i - (sin t)k B. T = (-sin t)i + (cos t)k; N = (-cos t)i + (sin t)k C. T = (sin t)i - (cos t)k; N = (cos t)i - (sin t)k; D. T = (-sin t)i + (cos t)k; N = (-cos t)i - (sin t)k
Solve the inequality symbolically. Express the solution set in interval notation.-11x + 6 ? -12x + 4
A. (-?, -2] B. [-2, ?) C. (-?, -11) D. (-11, ?)
Solve the problem.The length and width of a rectangle must have a sum of 40 feet. Find the dimensions of the rectangle whose area is as large as possible.
A. length 19 ft; width 21 ft
B. length 20 ft; width 20 ft
C. length 20 ft; width 60 ft
D. length 
ft; width 
ft
Solve the equation.15(7c - 5) = 8c - 3
A. c = 
B. c = 
C. c = 
D. c = - 