In the expression (j > 0 && j+1 == 10), which operator executes last?
a) >
b) &&
c) +
d) ==
b) &&
The precedences, higher to lower are: +, >, ==, &&. So the order is j+1, j>0, then (j+1)==10, then (finally) the ((j>0) && ((j+1) == 10))
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