How much air is needed to completely combust a mixture of 4000 ppmv butane and 8000 ppmv propane?
What will be an ideal response?
The total O2 required = 130,00 ppm + 40,000 ppm = 170,000 ppm In percent = 17%
Therefore there is sufficient O2 in air (21%) to burn this mixture of propane + butane
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