Solve using the substitution method. If the system has an infinite number of solutions, use set-builder notation to write the solution set. If the system has no solution, state this.a + 4b = 23a = -12b + 6
A. (4, 2)
B. {(a, b)|a = 4b + 2}
C. No solution
D. {(a, b)|a + 4b = 2}
Answer: D
Mathematics
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