Solve the initial value problem.Differential Equation:  = -3ti + 3tj + 5tkInitial Condition: r(0) = -4i + 6k

A. r(t) = (-3t2 - 8)i + 3t2j  + (5t2 + 12)k
B. r(t) = i + t2j  +  k
C. r(t) = i + t2j  -  k
D. r(t) = i + t2j  +  k

Answer: D

Mathematics

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