Activity C is directly preceded by two activities, activity A and activity B. Activity A has an expected time of five and early start time of six. Activity B has an expected time of seven and an early start time of seven. Activity C has an expected time of ten. What is the early start for activity C?
Activity A, early finish is 6 + 5 = 11.
Activity B, early finish is 7 + 7 = 14.
The early start for Activity 7 is the larger of the two early finish times; so the time is 14.
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