Rewrite the equation in standard form. Find the center and radius of the circle.x2 + y2 + 4y - 32 = 0
A. x2 + (y + 2)2 = 36
center (0, -2), r = 6
B. x2 + (y + 2)2 = 36
center (0, 2), r = 6
C. (x + 2)2 + y2 = 36
center (-2, 0), r = 6
D. x2 + (y - 2)2 = 36
center (0, 2), r = 6
Answer: A
Mathematics
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