A crank is being turned clockwise at 120 rev/min. The handle is 10 cm from the axle of the crank
An observer some distance away sees the crank edge-on so he only perceives the vertical motion of the crank and not the horizontal motion. What equation describes the motion of the handle seen by the observer if at t=0 the crank is at y = 0 and moving in the negative y direction?
A)
y = (10 cm)cos((12.6 rad/s)t +3?/2 )
B)
y = (10 cm)cos((12.6 rad/s + ?)t)
C)
y = (10 cm)cos((12.6 rad/s)t - ?/2 )
D)
y = (10 cm)cos((12.6 rad/s)t)
E)
y = (10 cm)cos((12.6 rad/s)t + ?/2 )
E
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