Find the location of the center, vertices, and foci for the hyperbola described by the equation.(y + 1)2 - 64(x - 1)2 = 64
A. Center: (1, -1); Vertices: (-1, -8) and (1, 8); Foci: (1, - 
) and (1, 
)
B. Center: (-1, 1); Vertices: (-1, -7) and (-1, 9); Foci: (-1, 1 - 
) and (-1, 1 + 
)
C. Center: (1, -1); Vertices: (1, -9) and (1, 7); Foci: (1, -1 - 
) and (1, -1 + 
)
D. Center: (1, -1); Vertices: (2, -8) and (2, 8); Foci: (2, 0 - 
) and (2, 0 + 
)
Answer: C
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B. y = - 
x2 + 22
C. y = 
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