If magnetic tape (pre?1980s) was ½ inch wide and stored data in nine tracks at 128 characters/inch, what was the areal density in bits per square inch? What is the areal density ratio between this and the platters of modern disk drives?
What will be an ideal response?
If the tape is ½ inch wide, one square inch of tape would be two inches long. At a density of 128 characters per inch, the density is 256 characters per square inch. A character occupies 9 bits, which makes the areal density 9 × 256 = 2,304 bits/square inch.
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