Solve the problem.A projectile is fired with an initial velocity of 450 feet per second at an angle of 45° with the horizontal. To the nearest foot, find the maximum altitude of the projectile. The parametric equations for the path of the projectile are x = (450 cos 45°)t, and y = (450 sin 45°)t - 16t2.
A. 1574 ft
B. 1598 ft
C. 1565 ft
D. 1582 ft
Answer: D
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