Solve the problem.The area of a triangular poster is 832 square centimeters. Its altitude is 12 feet shorter than twice its base. Find the lengths of the altitude and base.
A. base = 64 cm; altitude = 13 cm
B. base = 32 cm; altitude = 26 cm
C. base = 32 cm; altitude = 52 cm
D. base = 16 cm; altitude = 52 cm
Answer: C
Mathematics
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A. 
+ 
B. 
+ 
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+ 
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A. ln 
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