Solve.The period of vibration P for a pendulum varies directly as the square root of the length L. If the period of vibration is 4 sec when the length is 64 inches, what is the period when L = 3.0625 inches?
A. 5 sec
B. 4.75 sec
C. 0.875 sec
D. 4.25 sec
Answer: C
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Perform the division.
A. x2 - 5 B. x - 5 C. x + 25 D. x - 25
Find the area enclosed by the given curves.Find the area of the region in the first quadrant bounded on the left by the line y = 
and on the right by the curves y = tan 2 x and y = cot 2 x. (Round to four decimal places.)
A.
| 0.5858 |
B. 0.4126
C. 4.3094
D. 0.3094
Provide an appropriate response.What is the discriminant for 16x2 - 8x + 1 = 0? How many and what type of solutions does this equation have?
A. Discriminant: 64; Two rational solutions B. Discriminant: 63; Two irrational solutions C. Discriminant: -64; Two nonreal complex solutions D. Discriminant: 0; One rational solution
Use the change of base formula and the properties of logarithms to rewrite the expression as a single logarithm in the indicated base.log625 x20 + log125 y15 - log25 w10, base 5
A. log5 
B. log5 x5y5z5
C. log5(x5 + y5 - z5)
D. log5 