Complete the equation.
= 
A. 144
B. 6
C. 12
D. 36
Answer: B
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Use a graphing calculator to find the vertex of the graph of the function.f(x) = x2 + x + 3
A. (-0.5, 3) B. (-0.5, 2.75) C. (0.5, 2.75) D. (0.5, -2.75)
Solve the problem.A 2,000-L tank is initially filled with a copper sulfate solution with a concentration of 50 g/L. A copper sulfate solution with a concentration of 20 g/L flows into the tank at a rate of 8 L/min. The thoroughly mixed solution is drained from the tank at a rate of 8 L/min.(a) Write an initial value problem for the mass of the copper sulfate.(b) Solve the initial value problem.
A. (a) m'(t) = 0.004m + 160, m(0) = 50 (b) m = -39,950e0.004t + 320,000 B. (a) m'(t) = -0.004m + 20, m(0) = 50 (b) m = -39,950e-0.004t + 40,000 C. (a) m'(t) = -250m + 160, m(0) = 100,000 (b) m = 60,000e-0.004t + 320,000 D. (a) m'(t) = -0.004m + 160, m(0) = 100,000 (b) m = 60,000e-0.004t + 40,000
Determine whether any of the listed candidates has a majority.Four candidates running for mayor receive votes as follows:Ito: 43,191, Johnson: 19,196, Kennedy: 9598, Lieberman: 14,397
A. Yes B. No
Solve the problem. Suppose a student plans to drive from his home to New Haven 75 miles on a divided highway and 30 miles on an undivided highway. The speed limit is 70 mph on the divided highway and 50 mph on the undivided highway. Assume the driver drives nonstop. Let T(a) represent the driving time (in hours) if the student drives at a mph above the speed limits. By finding a formula for T(a), determine 
. What does your result mean in terms of the trip?
A. T(0) - T(10) = 0.23; the trip will take 0.23 hours more by driving at 10 mph over the speed limits than it would take driving at the speed limits. B. T(0) - T(10) = 0.37; the trip will take 0.37 hours less by driving at 10 mph over the speed limits than it would take driving at the speed limits. C. T(0) - T(10) = 0.37; the trip will take 0.37 hours more by driving at 10 mph over the speed limits than it would take driving at the speed limits. D. T(0) - T(10) = 0.23; the trip will take 0.23 hours less by driving at 10 mph over the speed limits than it would take driving at the speed limits.