Eliminate the parameter. Write the resulting equation in standard form.A circle: x = 2 + 5 cos t, y = 5 + 5 sin t
A. 
+ 
= 1
B. 
+ 
= 1
C. 
+ 
= 1
D. (x - 2)2 + (y - 5)2 = 25
Answer: C
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Solve the problem.Let u = 6i + j, v = i + j, and w = i - j. Find scalars a and b such that u = av + bw.
A. 6v + w B. 0.2857 v + 0.4000 w C. 3.500 v + 2.500w D. 6v - w
Find v ? u.v = 6i - 5j and u = -4i - 2j
A. -14 B. 2i - 7j C. -34 D. -24i + 10j
Determine the degree of the polynomial.2n4 + 5n3 - n2 - 8n - 8
A. 10 B. 2 C. 4 D. 5
Determine if the following is a linear equation in one variable. If not, state why.1.1x - 2.4 = 0.7x + 1.28
A. It is a linear equation in one variable. B. It is not a linear equation in one variable because it has more than one variable. C. It is not a linear equation in one variable because it is not an equation. D. It is not a linear equation in one variable because 1.1x has an exponent other than 1.