A 90% concentration of alcohol is in stock in the laboratory. The percent solution required is 70%. How is 200 mL of 70% made? Give the formula and the final answer.
What will be an ideal response?
C1
V1 = C2
V2
(90%)(x mL ) = (70%)(200 mL)
90x = 14,000
x = 155.5 mL 90% diluted up to 200 mL with water
or
add 44.5 mL water to 155.5 mL of the 90% alcohol
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