Jackson Farms have allotted a certain amount of land for cultivating soybeans, corn, and wheat. Cultivating 1 acre of soybeans requires 4 labor-hours, and cultivating 1 acre of corn or wheat requires 7 labor-hours. The cost of seeds for 1 acre of soybeans is $13, for 1 acre of corn is $20, and for 1 acre of wheat is $7. If all resources are to be used, how many acres of each crop should be cultivated if the following hold?
1,500 acres of land are allotted, 9,600 labor-hours are available, and $18,800 is available for seeds.
a. 300 acres of soybeans, 500 acres of corn, 700 acres of wheat
b. 100 acres of soybeans, 600 acres of corn, 700 acres of wheat
c. 100 acres of soybeans, 500 acres of corn, 800 acres of wheat
d. 300 acres of soybeans, 600 acres of corn, 800 acres of wheat
a. 300 acres of soybeans, 500 acres of corn, 700 acres of wheat
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Find the gradient field F of the function f.f(x, y, z) = z sin (x + y + z)
A. F = -cos xi - cos yj + (sin z - z cos z)k B. F = -z cos(x + y + z)i - z cos(x + y +z)j + (sin(x + y + z) - zcos(x + y + z))k C. F = cos xi + cos yj + (sin z + z cos z)k D. F = z cos(x + y + z)i + z cos(x + y +z)j + (sin(x + y + z) + zcos(x + y + z))k
Find the indicated root of the given equation by using Newton's method.
+ 
= 
+ 
(between 1 and 2)
A. 1.5615825 B. 1.5615852 C. 1.5615528 D. 1.5615582
Solve the problem.Let g(x) = 6x + x2. Find a so that g(a) = -5.
A. {0, -5}
B. 
C. {-5, -1}
D. {5, 1}
Solve the problem.One Internet service provider has the following rate schedule for high-speed Internet service:Monthly service charge$18.001st 50 hours of usefreeNext 50 hours of use$0.25/hourOver 100 hours of use$1.00/hourWhat is the charge for 50 hours of high-speed Internet use in one month?What is the charge for 75 hours of high-speed Internet use in one month?What is the charge for 135 hours of high-speed Internet use in one month?
Fill in the blank(s) with the appropriate word(s).