Solve the problem.The distance D in feet that an object has fallen after t seconds is given by D(t) = 16t2. (i) Evaluate D(2) and D(3). (ii) Calculate the average rate of change of D from 2 to 3. Interpret the result.
A. (i) 64, 144
(ii) 16; the object's average speed from 2 to 3 seconds is 16 ft/sec.
B. (i) 32, 48
(ii) 80; the object's average speed from 2 to 3 seconds is 80 ft/sec.
C. (i) 32, 48
(ii) 16; the object's average speed from 2 to 3 seconds is 16 ft/sec.
D. (i) 64, 144
(ii) 80; the object's average speed from 2 to 3 seconds is 80 ft/sec.
Answer: D
You might also like to view...
Solve.-8.7 ? 1.3 - 0.2(5x + 3) < 7.62
A. -5.72 ? x < 6.8 B. -5.72 < x ? 6.8 C. -6.92 ? x < 9.4 D. -6.92 < x ? 9.4
Add and subtract as indicated. Simplify and leave the numerator and denominator in your answer in factored form. +
A.
B.
C.
D.
Graph the equation using the indicated viewing window.y = x + 4;X min = -5X max = 5X scl = 1Y min = -4Y max = 4Y scl = 1
A.
B.
C.
D.
Insert either < or > to make the statement true.-4 _____ -3
A. > B. <