Based on the dangling-else discussion state the output for each of the following code snippets when x is 9 and y is 11 and when x is 11 and y is 9. We eliminated the indentation from the following code to make the problem more challenging.

Question

```
if (x < 10)
{
if (y > 10)
cout << "*****" << endl;
}
else
{
cout << "#####" << endl;
cout << "$$$$$" << endl;
}
```

Answer 1

```
When x is 9 and y is 11
*****
When x is 11 and y is 9
#####
$$$$$
```